{"id":371,"date":"2025-07-29T10:00:00","date_gmt":"2025-07-29T10:00:00","guid":{"rendered":"https:\/\/www.rightlobemath.com\/blog\/?p=371"},"modified":"2025-07-29T10:00:00","modified_gmt":"2025-07-29T10:00:00","slug":"abacus-math-program-lesson-8-ten-pair-complement-subtraction-part-2","status":"publish","type":"post","link":"https:\/\/sumomath.com\/content\/abacus-math-program-lesson-8-ten-pair-complement-subtraction-part-2\/","title":{"rendered":"Abacus Math Program &#8211; Lesson 8 &#8211; Ten Pair Complement Subtraction Part 2"},"content":{"rendered":"<p>Continuing from\u00a0<a href=\"https:\/\/www.sumomath.com\/content\/abacus-math-program-lesson-7-ten-pair-complement-subtraction-part-1\/\"><u>Lesson 7 Subtraction Part 1<\/u><\/a>\u00a0we will look at a few more 10 pair complement\u00a0subtraction examples. Again there are 5 possible 10 pair complements: 9-1, 8-2, 7-3, 6-4, 5-5. All of these pairs are reversible meaning we can use the complement pair, 9-1, for both the problem\u00a010-1 just as we can use the same pair for the problem\u00a010-9. So the following examples will look at some of the reverse pair\u00a0 possibilities such as subtracting -1, -2, -3, -4.<\/p>\n<p>In the first example we start by adding 9 to the abacus. Next we add 5 to 9 but notice that we will need to use the 10 pair addition rule. So first add 1 to the next rod left, rod A, and then subtract 5, the 10 pair complement of 5, from 9 on rod B. The interim sum is now 14. Next subtract 3 from 4 on rod B for an interim sum of 11. Lastly subtract 2 from 11 by subtracting 2 from 1 on rod B. But since there are not enough beads touching the reckoning bar we will need to use the 10 pair subtraction rule. So first subtract 1 from the next rod left, rod A, and then add 8, the 10 pair complement of 2, to 1 on rod B for a final answer of 9.<\/p>\n<p>\t\t\t\t\t\t\t\t\t\t<img loading=\"lazy\" decoding=\"async\" width=\"472\" height=\"358\" src=\"https:\/\/www.sumomath.com\/content\/wp-content\/uploads\/2020\/02\/lesson72example1.png\" alt=\"\" srcset=\"https:\/\/www.sumomath.com\/content\/wp-content\/uploads\/2020\/02\/lesson72example1.png 472w, https:\/\/www.sumomath.com\/content\/wp-content\/uploads\/2020\/02\/lesson72example1-300x228.png 300w\" sizes=\"auto, (max-width: 472px) 100vw, 472px\" \/>\t\t\t\t\t\t\t\t\t\t\t<\/p>\n<p>In the next example we start by adding 8 to the abacus. Next we add 4 to 8 using the 10 pair addition rule. So first add 1 to the next rod left, rod A, and then subtract 6, the 10 pair complement of 4, from 8 on rod B. The interim sum is now 12. Next subtract 3 from 12 by subtracting 3 from 2 on rod B. Again we will need to use the 10 pair subtraction rule. First subtract 1 from the next rod left, rod A, and then add 7, the 10 pair complement of 3, to 2 on rod B. The interim sum is now 9. Finally subtract 7 from 9 on rod B for a final answer of 2.<\/p>\n<p>\t\t\t\t\t\t\t\t\t\t<img loading=\"lazy\" decoding=\"async\" width=\"472\" height=\"358\" src=\"https:\/\/www.sumomath.com\/content\/wp-content\/uploads\/2020\/02\/lesson72example2.png\" alt=\"\" srcset=\"https:\/\/www.sumomath.com\/content\/wp-content\/uploads\/2020\/02\/lesson72example2.png 472w, https:\/\/www.sumomath.com\/content\/wp-content\/uploads\/2020\/02\/lesson72example2-300x228.png 300w\" sizes=\"auto, (max-width: 472px) 100vw, 472px\" \/>\t\t\t\t\t\t\t\t\t\t\t<\/p>\n<p>In the last example we start by adding 6 to the abacus. Next add 4 to 6 using the 10 pair addition rule. So first add 1 to the next rod left, rod A, and then subtract 6, the 10 pair complement of 4, from 6 on rod B. The interim sum is now 10. Next subtract 1 from 10 by subtracting 1 from 0 on rod B. Again we will need to use the 10 pair subtraction rule. First subtract 1 from 1 on the next rod left, rod A, and add 9, the 10 pair complement of 1, to 0 on rod B. The interim sum is now 9. Lastly add 8 to 9 on rod B by using the 10 pair addition rule. First add 1 to 0 on next rod left, rod A, and subtract 2, the 10 pair complement of 8, from 9 on rod B. The final answer is 17.<\/p>\n<p>\t\t\t\t\t\t\t\t\t\t<img loading=\"lazy\" decoding=\"async\" width=\"472\" height=\"359\" src=\"https:\/\/www.sumomath.com\/content\/wp-content\/uploads\/2020\/02\/lesson72example3.png\" alt=\"\" srcset=\"https:\/\/www.sumomath.com\/content\/wp-content\/uploads\/2020\/02\/lesson72example3.png 472w, https:\/\/www.sumomath.com\/content\/wp-content\/uploads\/2020\/02\/lesson72example3-300x228.png 300w\" sizes=\"auto, (max-width: 472px) 100vw, 472px\" \/>\t\t\t\t\t\t\t\t\t\t\t<\/p>\n<p>Next up <a href=\"https:\/\/www.sumomath.com\/content\/abacus-math-program-lesson-9-five-pair-complement-part-1\/\"><u>Lesson 9 introducing the 5 Pair<\/u><\/a>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Continuing from\u00a0Lesson 7 Subtraction Part 1\u00a0we will look at a few more 10 pair complement\u00a0subtraction examples. Again there are 5 possible 10 pair complements: 9-1, 8-2, 7-3, 6-4, 5-5. All of these pairs are reversible meaning we can use the complement pair, 9-1, for both the problem\u00a010-1 just as we can use the same pair<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[],"tags":[],"class_list":["post-371","post","type-post","status-publish","format-standard","hentry"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.4 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>Abacus Math Program - Lesson 8 - Ten Pair Complement Subtraction Part 2 - sumomath.com<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/sumomath.com\/content\/abacus-math-program-lesson-8-ten-pair-complement-subtraction-part-2\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Abacus Math Program - Lesson 8 - Ten Pair Complement Subtraction Part 2 - sumomath.com\" \/>\n<meta property=\"og:description\" content=\"Continuing from\u00a0Lesson 7 Subtraction Part 1\u00a0we will look at a few more 10 pair complement\u00a0subtraction examples. 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